Consider the structure of `CsCl` (`8: 8` coordination). How many `Cs^(o+)` ions occupy the second nearest neighbour locations of a `Cs^(o+)` ion?
8
24
6
16

Options

A. `8`
B. `24`
C. `6`
D. `16`

Explanation

To solve the problem of how many Cs⁺ ions occupy the second nearest neighbor locations of a Cs⁺ ion in the CsCl structure, we can follow these steps:

### Step 1: Understand the Structure of CsCl
CsCl crystallizes in a body-centered cubic (BCC) lattice structure. In this structure, each Cs⁺ ion is surrounded by Cl⁻ ions, and vice versa.

**Hint:** Visualize the arrangement of ions in the CsCl lattice. Cs⁺ ions are at the corners and the center of the cube.

### Step 2: Identify the Nearest Neighbors
In the CsCl structure, each Cs⁺ ion has 8 Cl⁻ ions as its nearest neighbors. This is important because it helps us understand the spatial arrangement of the ions.

**Hint:** Remember that nearest neighbors are the ions that are directly adjacent to a given ion.

### Step 3: Determine the Second Nearest Neighbors
The second nearest neighbors of a Cs⁺ ion are those ions that are not directly adjacent but are still within the lattice. In the case of the CsCl structure, each Cs⁺ ion has 6 Cs⁺ ions as its second nearest neighbors.

**Hint:** Consider the geometry of the cube and how ions are positioned relative to each other.

### Step 4: Conclusion
Thus, the number of Cs⁺ ions that occupy the second nearest neighbor locations of a Cs⁺ ion in the CsCl structure is **6**.

**Final Answer:** 6