A `TV` in fcc is formed by atoms at

Options

A. `3` corners `+ 1` face centre
B. `3` face centres `+ 1` corner
C. `2` face centres `+ 2` corners
D. `2` face centres `+ 1` corner `+ 1` body centre

Explanation

To determine the positions of atoms that form a tetrahedral void in a face-centered cubic (FCC) structure, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the FCC Structure**:
- In a face-centered cubic (FCC) lattice, atoms are located at each of the corners of the cube as well as at the centers of each of the cube's faces.

2. **Visualize the Tetrahedral Void**:
- A tetrahedral void is formed when four atoms are arranged in a tetrahedral geometry. In an FCC structure, this void is created by the arrangement of atoms at specific positions.

3. **Identify the Atoms Involved**:
- In the case of the tetrahedral void in an FCC lattice, the void is formed by:
- **Three atoms located at the face centers** of the cube.
- **One atom located at one of the corners** of the cube.

4. **Conclusion**:
- Therefore, the tetrahedral void in an FCC structure is formed by three face-centered atoms and one corner atom.

5. **Select the Correct Option**:
- From the provided options, the correct answer is: **three face centers and one corner**.

### Final Answer:
The tetrahedral void in an FCC structure is formed by three face centers and one corner atom.

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