The number of unit cells in `58.5` g of NaCl is nearly :

Options

A. `6 xx 10^(20)`
B. `3 xx 10^(22)`
C. `1.5 xx 10^(23)`
D. `0.5 xx 10^(24)`

Answer

C

Explanation

`58.5 g NaCl = 1 mol`
`= 6.02 xx 10^(23) Na^(o+)Cl^(ɵ)` units
One unit cell contains `4 Na^(o+)Cl^(ɵ)` units. Hence, number of the unit cell present `= 6.02 xx 10^(23)//4 = 1.5 xx 10^(23)`