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In NaCl, the chloride ions occuphy the s...

In `NaCl`, the chloride ions occuphy the space in a fashion of

A

fcc

B

bcc

C

Both

D

None

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The correct Answer is:
To solve the question regarding how chloride ions occupy space in NaCl, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Structure of NaCl**: - Sodium chloride (NaCl) crystallizes in a face-centered cubic (FCC) lattice structure. 2. **Understand the FCC Lattice**: - In an FCC lattice, there are atoms located at each of the corners and at the centers of each face of the cube. This arrangement allows for a close packing of ions. 3. **Determine the Position of Chloride Ions**: - In the case of NaCl, the chloride ions (Cl⁻) occupy the FCC lattice sites. This means that the Cl⁻ ions are positioned at the face centers and the corners of the cubic unit cell. 4. **Identify the Position of Sodium Ions**: - The sodium ions (Na⁺) occupy the octahedral voids within the FCC lattice. This is important to note, as it explains the arrangement of the ions in the crystal structure. 5. **Conclude the Arrangement**: - Therefore, in NaCl, the chloride ions occupy the face-centered cubic lattice sites, while the sodium ions occupy the octahedral voids. ### Final Answer: The chloride ions in NaCl occupy the FCC lattice sites.
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CENGAGE CHEMISTRY ENGLISH-SOLID STATE-Exercises (Single Correct)
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  4. Potassium crystallizes with a

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  6. The number of unit cells in 58.5 g of NaCl is nearly :

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  7. The number of octahedral sites per sphere in fcc structure is

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  8. The packing fraction for a body-centred cube is

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  9. Which of the following has Frenkel defect?

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  10. In NaCl, the chloride ions occuphy the space in a fashion of

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  11. To get n-type of doped semi conductor, the impurity to be added to sil...

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  12. The range of radius ratio (cationic to anionic) for an octahedral arra...

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  13. When molten zinc is cooled to solid state, it assumes hcp structure. T...

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  17. Which of the following metal oxides is antiferromagnetic in nature ?

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  18. What are types of following semiconductors I and II.

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