Home
Class 12
CHEMISTRY
In the structure of diamond, carbon atom...

In the structure of diamond, carbon atoms appear at
a.`0, 0, 0`, and `(1)/(2), (1)/(2), (1)/(2)`
b.`(1)/(4), (1)/(4), (1)/4`, and `(1)/(2), (1)/(2), (1)/(2)`
c.`0, 0, 0`, and `(1)/(4), (1)/(4), (1)/(4)`
d.`0, 0, 0`, and `(3)/(4), (3)/(4), (3)/(4)`

A

`0, 0, 0`, and `(1)/(2), (1)/(2), (1)/(2)`

B

`(1)/(4), (1)/(4), (1)/4`, and `(1)/(2), (1)/(2), (1)/(2)`

C

`0, 0, 0`, and `(1)/(4), (1)/(4), (1)/(4)`

D

`0, 0, 0`, and `(3)/(4), (3)/(4), (3)/(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the positions of carbon atoms in the structure of diamond, we need to analyze the crystal structure of diamond, which is a type of face-centered cubic (FCC) lattice with additional carbon atoms located at tetrahedral sites. ### Step-by-Step Solution: 1. **Understanding the Diamond Structure**: - Diamond has a face-centered cubic (FCC) structure. - In addition to the atoms at the corners and face centers of the cube, diamond has carbon atoms located at tetrahedral positions. 2. **Identifying the Positions**: - The carbon atoms in diamond occupy specific positions: - One carbon atom is located at the origin, which is represented as (0, 0, 0). - Another carbon atom is located at the position (1/2, 1/2, 1/2), which is the body center of the cubic unit cell. 3. **Evaluating the Options**: - **Option a**: (0, 0, 0) and (1/2, 1/2, 1/2) – This matches our identified positions. - **Option b**: (1/4, 1/4, 1/4) and (1/2, 1/2, 1/2) – This does not match as (1/4, 1/4, 1/4) is not a position for carbon in diamond. - **Option c**: (0, 0, 0) and (1/4, 1/4, 1/4) – This does not match as (1/4, 1/4, 1/4) is not a position for carbon in diamond. - **Option d**: (0, 0, 0) and (3/4, 3/4, 3/4) – This does not match as (3/4, 3/4, 3/4) is also not a position for carbon in diamond. 4. **Conclusion**: - The correct positions of carbon atoms in the diamond structure are given by option **a**: (0, 0, 0) and (1/2, 1/2, 1/2). ### Final Answer: **Option a: (0, 0, 0) and (1/2, 1/2, 1/2)**

To determine the positions of carbon atoms in the structure of diamond, we need to analyze the crystal structure of diamond, which is a type of face-centered cubic (FCC) lattice with additional carbon atoms located at tetrahedral sites. ### Step-by-Step Solution: 1. **Understanding the Diamond Structure**: - Diamond has a face-centered cubic (FCC) structure. - In addition to the atoms at the corners and face centers of the cube, diamond has carbon atoms located at tetrahedral positions. ...
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Assertion-Reasoning)|19 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Interger)|9 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Multiple Correct)|39 Videos
  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise SUBJECTIVE TYPE|4 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 2.3 (Objective)|9 Videos

Similar Questions

Explore conceptually related problems

The points (-2, -1), (1, 0), (4, 3) and (1, 2) are

The orthocentre of the triangle formed by the lines x y=0 and x+y=1 is (a) (1/2,1/2) (b) (1/3,1/3) (c) (0,0) (d) (1/4,1/4)

For 2 times 2 matrices A,B and I, if A+B=I and 2A-2B=I , then A equals 1) [[(1)/(4),0],[0,(1)/(4)]] 2) [[(1)/(2),0],[0,(1)/(2)]] 3) [[(3)/(4),0],[0,(3)/(4)]], 4) [[1,0],[0,1]]

If A[{:(3,-4),(1,1),(2,0):}] and B=[{:(2,1,2),(1,2,4):}] and B=[{:(4,1),(2,3),(1,2):}]

The orthocentre of the triangle formed by the lines x y=0 and x+y=1 is (1/2,1/2) (b) (1/3,1/3) (0,0) (d) (1/4,1/4)

The focus of the parabola y=2x^2+x is a. (0,0) b. (1//2,1//4) c. (-1//2,0) d. (-1//4,1//8)

By plotting the following points check whether they are collinear or not (i) (1,1), (2,2),(4,4) (ii) (1,0), (-3,0), (0,0) (iii) (2,-2), (0,0), (-3,4)

If A=[(1,0,0),(0,-1,0),(0,0,2)] and B=[(2,0,0),(0, 3,0),(0,0,-1)] , find A+B , 3A+4B .

The lines ax + by + c = 0, where 3a + 2b + 4c= 0, are concurrent at the point (a) (1/2 ,3/4) (b) (1,3) (c) (3,1) (d) (3/4 ,1/2)

If A=[(3,-3,4),(2,-3,4),(0,-1,1)] , then A^(-1)=

CENGAGE CHEMISTRY ENGLISH-SOLID STATE-Exercises (Single Correct)
  1. In the crystals of which of the following ionic compounds would you ex...

    Text Solution

    |

  2. Schottky defect is observed in crystals when

    Text Solution

    |

  3. How many kinds of space lattices are possible in a crystal?

    Text Solution

    |

  4. Potassium crystallizes with a

    Text Solution

    |

  5. A compound formed by elements A and B crystallizes in the cubic arrang...

    Text Solution

    |

  6. The number of unit cells in 58.5 g of NaCl is nearly :

    Text Solution

    |

  7. The number of octahedral sites per sphere in fcc structure is

    Text Solution

    |

  8. The packing fraction for a body-centred cube is

    Text Solution

    |

  9. Which of the following has Frenkel defect?

    Text Solution

    |

  10. In NaCl, the chloride ions occuphy the space in a fashion of

    Text Solution

    |

  11. To get n-type of doped semi conductor, the impurity to be added to sil...

    Text Solution

    |

  12. The range of radius ratio (cationic to anionic) for an octahedral arra...

    Text Solution

    |

  13. When molten zinc is cooled to solid state, it assumes hcp structure. T...

    Text Solution

    |

  14. Superconductors are derived from the compounds of

    Text Solution

    |

  15. A semiconductor of Ge can be made p-type by adding

    Text Solution

    |

  16. The interionic distance for cesium chloride crystal will be

    Text Solution

    |

  17. Which of the following metal oxides is antiferromagnetic in nature ?

    Text Solution

    |

  18. What are types of following semiconductors I and II.

    Text Solution

    |

  19. In the structure of diamond, carbon atoms appear at a.0, 0, 0, and (...

    Text Solution

    |

  20. Which of the following figures represets the cross-section of an octah...

    Text Solution

    |