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A solid has a structure in which X atoms...

A solid has a structure in which `X` atoms are located at cubic corners of unit cell, `O` atom are at the edge centres and `Y` atoms at cube centre.
Then the formula of compound is `X_(a)Y_(b)O_(c)`
If two atoms of `O` missing from any of two edge centres per unit cell, then the molecular formula is `X_(a)Y_(b)O_(z)`. Then, find the value of `(x + y + z) - (a + b+ c)`.

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To solve the problem step by step, we will analyze the structure of the solid and calculate the number of atoms of each type in the unit cell. ### Step 1: Determine the number of X atoms in the unit cell. - X atoms are located at the corners of the cubic unit cell. - There are 8 corners in a cube, and each corner contributes \( \frac{1}{8} \) of an atom to the unit cell. \[ \text{Number of X atoms} = 8 \times \frac{1}{8} = 1 \] ### Step 2: Determine the number of O atoms in the unit cell. - O atoms are located at the edge centers of the cubic unit cell. - There are 12 edges in a cube, and each edge contributes \( \frac{1}{4} \) of an atom to the unit cell. \[ \text{Number of O atoms} = 12 \times \frac{1}{4} = 3 \] ### Step 3: Determine the number of Y atoms in the unit cell. - Y atoms are located at the body center of the cubic unit cell. - There is 1 body center in a cube, and it contributes 1 atom to the unit cell. \[ \text{Number of Y atoms} = 1 \] ### Step 4: Write the initial formula of the compound. From the calculations: - Number of X atoms = 1 - Number of Y atoms = 1 - Number of O atoms = 3 Thus, the initial formula is: \[ X_a Y_b O_c = X_1 Y_1 O_3 \] ### Step 5: Adjust the number of O atoms due to missing atoms. - It is given that 2 O atoms are missing from the edge centers. - After removing 2 O atoms from the edge centers, the number of O atoms becomes: \[ \text{Remaining O atoms} = 3 - 2 = 1 \] ### Step 6: Calculate the new number of O atoms in terms of contributions. Since there are 10 edge centers remaining (12 - 2), the contribution from these edge centers is: \[ \text{Number of O atoms} = 10 \times \frac{1}{4} = 2.5 \] ### Step 7: Write the revised formula of the compound. With the new counts: - Number of X atoms = 1 - Number of Y atoms = 1 - Number of O atoms = 2.5 The revised formula is: \[ X_1 Y_1 O_{2.5} \] ### Step 8: Express the revised formula in terms of integers. To express the formula in whole numbers, we can multiply all subscripts by 2: \[ X_2 Y_2 O_5 \] ### Step 9: Identify values of x, y, z, a, b, c. From the formulas: - \( x = 2 \) - \( y = 2 \) - \( z = 5 \) - \( a = 1 \) - \( b = 1 \) - \( c = 3 \) ### Step 10: Calculate \( (x + y + z) - (a + b + c) \). \[ (x + y + z) = (2 + 2 + 5) = 9 \] \[ (a + b + c) = (1 + 1 + 3) = 5 \] \[ (x + y + z) - (a + b + c) = 9 - 5 = 4 \] ### Final Answer: The value of \( (x + y + z) - (a + b + c) \) is \( 4 \). ---

To solve the problem step by step, we will analyze the structure of the solid and calculate the number of atoms of each type in the unit cell. ### Step 1: Determine the number of X atoms in the unit cell. - X atoms are located at the corners of the cubic unit cell. - There are 8 corners in a cube, and each corner contributes \( \frac{1}{8} \) of an atom to the unit cell. \[ \text{Number of X atoms} = 8 \times \frac{1}{8} = 1 ...
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