The edge length of unit cell of a metal having molecular weight `75 g mol^(-1)` is `5 Å` which crystallizes in cubic lattice. If the density is `2 g cm^(-3)`, then find the radius of metal atom `(N_(A) = 6 xx 10^(23))`. Give the answer in pm.

Explanation

To find the radius of the metal atom given the molecular weight, edge length, and density, we can follow these steps:

### Step 1: Use the formula for density
The density (\( \rho \)) of a crystalline solid can be expressed using the formula:
\[ \rho = \frac{Z \times M}{N_A \times a^3} \]
where:
...