Home
Class 12
CHEMISTRY
The vapour pressure of a 5% aqueous solu...

The vapour pressure of a `5%` aqueous solution of a non-volatile organic substance at `373 K`. Is `745 mm`. Calculate the molecular mass of the solute.

Text Solution

AI Generated Solution

To solve the problem of calculating the molecular mass of the solute from the given data, we can follow these steps: ### Step 1: Understand the Given Data - The vapor pressure of the solution (P_s) = 745 mm Hg - The vapor pressure of the pure solvent (P_0) = 760 mm Hg (for water at 373 K) - The weight percentage of the solute = 5% - The weight of the solvent = 100 g - 5 g = 95 g ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Multiple Correct)|25 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 2.3 (Objective)|9 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

The vapour pressure of a dilute aqueous solution of glucose is 700 mm of Hg at 373 K . Calculate the (a) molality and (b) mole fraction of the solute.

The osmotic pressure of 5% solution of urea at 300 K is

The osmotic pressure of 5% solution of urea at 323 K is

The osmotic pressure of 5% solution of urea at 273 K is

The osmotic pressure of 5% solution of urea at 298 K is

The osmotic pressure of 5% solution of urea at 258 K is

The vapour pressure of an aqueous solution of glucose is 750 mm of Hg at 373 K . Calculate molality and mole fraction of solute.

A 5 per cent aqueous solution by mass of a non-volatile solute boils at 100.15^(@)C . Calculate the molar mass of the solute. K_(b)=0.52 K kg "mol"^(-1) .

The relative lowering of vapour pressure of an aqueous solution of a non-volatile solute of molecular weight 60 (which neither dissociates nor associates in the solution) is 0.018. If K_(f) of water is 1.86^(@)Cm^(-1) the depression in freezing point will be :

Why vapour pressure of a liquid decreases when a non - volatile solute is added to it ?