At `298 K` , the vapour pressure of water is `23.75 mm Hg`. Calculate the vapour pressure at the same temperature over `5%` aqueous solution of urea. `[CO(NH_(2))_(2)]`.

Explanation

To calculate the vapor pressure of a 5% aqueous solution of urea at 298 K, we will use Raoult's Law, which states that the vapor pressure of a solvent in a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution.

### Step-by-step Solution:

1. **Identify the Given Data:**
- Vapor pressure of pure water (P₀) at 298 K = 23.75 mm Hg
- Mass of urea (solute) = 5 g
- Mass of water (solvent) = 100 g - 5 g = 95 g
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