Liquids `A` and `B` form an ideal mixture, in which the mole fraction of `A` is `0.25`. At temperature `T`, a small quantity of the vapour in equilibrium with the liquid is collected and condensed. This process is repeated for a second time with first condensate. The second condensate now contains 0.645 mole fraction of `A`. Calculate the ratio `(P_(A)^(@)//P_(B)^(@))`. What will be the mole fraction of `B` in the third condensate?

Explanation

To solve the problem step by step, we will follow the outlined approach based on the information given:

### Step 1: Define the mole fractions
Given that the mole fraction of liquid A, \( x_A \), is 0.25, we can find the mole fraction of liquid B, \( x_B \):
\[ x_B = 1 - x_A = 1 - 0.25 = 0.75 \]

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