A certain solution of `1 m` benzoic acid in benzene has a freezing point of `3.1^(@)C` and a normal boiling point of `82.6 ^(@)C`. The freezing point of benzene is `5.5^(@)C`. And its boiling point is `80.1^(@)C`. Analyze the state of the solute (benzoic acid ) at two temperature and comment .

Explanation

To analyze the state of the solute (benzoic acid) at two temperatures based on the provided data, we will follow these steps:

### Step 1: Identify the Given Data
- **Molality of benzoic acid (m)**: 1 m
- **Freezing point of the solution (Tf)**: 3.1 °C
- **Boiling point of the solution (Tb)**: 82.6 °C
- **Freezing point of pure benzene (T°f)**: 5.5 °C
- **Boiling point of pure benzene (T°b)**: 80.1 °C
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