If the radiator of an automobile contains `12 L` of water, how much would the freezing point be lowered by the addition of `5 kg` of prestone `("glycol" C_(2)H_(4)((OH)_(2))`. How many kg of Zeron (methyl alcohol) would be required to produce the same result?

Explanation

To solve the problem, we need to determine how much the freezing point of water is lowered by the addition of 5 kg of ethylene glycol (C₂H₄(OH)₂) and then find out how much methyl alcohol (Zeron) would be required to achieve the same freezing point depression.

### Step 1: Calculate the molality of ethylene glycol in water.

1. **Find the number of moles of ethylene glycol (C₂H₄(OH)₂)**:
- The molar mass of ethylene glycol (C₂H₄(OH)₂) is calculated as follows:
- Carbon (C): 2 × 12 g/mol = 24 g/mol
- Hydrogen (H): 6 × 1 g/mol = 6 g/mol
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