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0.5 g KCl was dissolved in 100 g water, ...

`0.5 g` `KCl` was dissolved in `100 g` water, and the solution, originally at `20^(@)C` froze at `-0.24^(@)C`. Calculate the percentage ionization of salt. `K_(f)` per `1000 g` of water =`1.86^(@)C`.

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To solve the problem step by step, we will follow the outlined approach: ### Step 1: Identify the Given Data - Mass of KCl (solute) = 0.5 g - Mass of water (solvent) = 100 g - Freezing point depression (ΔTf) = -0.24 °C - Cryoscopic constant (Kf) for water = 1.86 °C kg/mol - Molar mass of KCl = 74.5 g/mol ...
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