`0.5 m` solution of acetic acid `(Mw=60)` in benzene `(Mw=78)` boils at `80.80^(@)C`. The normal boiling point of benzene is `80.10^(@)C`. And `Delta_(vap)H=30.775 kJ mol^(-1)`. Calculate the percent of association of acetic acid in benzene.

Explanation

To calculate the percent of association of acetic acid in benzene, we will follow these steps:

### Step 1: Calculate the change in boiling point (ΔTb)
The normal boiling point of benzene (Tb0) is given as 80.10°C, and the boiling point of the solution (Tb) is 80.80°C.

\[ \Delta T_b = T_b - T_{b0} = 80.80°C - 80.10°C = 0.70°C \]
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