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The freezing point of a solution contain...

The freezing point of a solution containing 0.2 g of acetic acid in benzene is lowered by `0.45^(@)C`. Colculate the degree of dimerization of acetic acid in benzene . `K_(f)` for benzene is 5.12 K`"mol"^(-1) `kg:

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`DeltaT_(f)=iK_(f)m`,`0.45=I xx 5.12 xx(0.2 xx 100)/(60 xx 20)`
`:.i=0.527`

` i=1-alpha+(alpha/2)=1-(alpha/2)`
`0.527 = 1-(alpha/2) rArr alpha =0.946`
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The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))

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The freezing point of a solution containing of 0.2g of acetic acid in 20.0g of benzene is lowered 0.45^(@)C . Calculate. (i) the molar mass of acetic acid from this data (ii) Van't Hoff factor [For benzene, K_(f)=5.12K kg "mol"^(-1) ] What conclusion can you draw from the value of Van't Hoff factor obtained ?

The freezing point of a solution containing 0*3 gms of acetic acid in 30 gms of benzene is lowered by 0*45 K . Calculate the van't Hoff factor. (At. wt. of C = 12, H = 1, 0 = 16, K_f " for benzene " = 5.12 " K kg mole"^(-1) ).

When 0.4 g of acetic acid is dissolved in 40 g of benzene, the freezing point of the solution is lowered by 0.45 K. Calculate the degree of association of acetic acid. Acetic acid forms dimer when dissolved in benzene. ( K_(f) for benzene = 5.12 K kg mol^(-1) at.wt. C = 12, H = 1, O = 16)

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The freezing point of benzene decreases by 0.45^(@)C when 0.2 g of acetic acid is added to 20 g of benzene. IF acetic acid associates to form a dimer in benzene, percentage association of acetic acid in benzene will be (K_(f) "for benzene" = 5.12 K kg mol^(-1))

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