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Which of the following is/are ture?...

Which of the following is/are ture?

A

For the same solution, elevation in boiling point =depression in freezing point.

B

The Van't Hoff factor for a dilute solution of `BaCl_(2)` is `3`.

C

The elevation in boiling point is due to increase in vapour pressure.

D

The depression in freezing point is due to decrease in vapour pressure.

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The correct Answer is:
To determine which of the given statements are true, let's analyze each option step by step. ### Step 1: Analyze Option A **Statement**: For the same solution, elevation in boiling point equals depression in freezing point. **Explanation**: - The elevation in boiling point (\( \Delta T_B \)) and depression in freezing point (\( \Delta T_F \)) can be expressed as: \[ \Delta T_B = i \cdot K_B \cdot m \] \[ \Delta T_F = i \cdot K_F \cdot m \] - Here, \( i \) is the van 't Hoff factor, \( K_B \) is the ebullioscopic constant, \( K_F \) is the cryoscopic constant, and \( m \) is the molality of the solution. - For the same solution, since \( i \), \( K_B \), and \( K_F \) are constants, we can conclude that \( \Delta T_B \) can be equal to \( \Delta T_F \) under certain conditions. Thus, this statement is **true**. ### Step 2: Analyze Option B **Statement**: The van 't Hoff factor for a dilute solution of BaCl2 is 3. **Explanation**: - BaCl2 dissociates in solution as follows: \[ \text{BaCl}_2 \rightarrow \text{Ba}^{2+} + 2 \text{Cl}^- \] - This means one formula unit of BaCl2 produces 3 particles (1 Ba²⁺ and 2 Cl⁻). - Therefore, the van 't Hoff factor \( i \) for BaCl2 is indeed 3. Thus, this statement is **true**. ### Step 3: Analyze Option C **Statement**: The elevation in boiling point is due to an increase in vapor pressure. **Explanation**: - The elevation in boiling point occurs because the vapor pressure of the solution is lower than that of the pure solvent. As a result, a higher temperature is required to reach the boiling point. - Therefore, the statement that the elevation in boiling point is due to an increase in vapor pressure is incorrect. Thus, this statement is **false**. ### Step 4: Analyze Option D **Statement**: The depression in freezing point is due to a decrease in vapor pressure. **Explanation**: - The depression in freezing point occurs because the vapor pressure of the solution is lower than that of the pure solvent. This decrease in vapor pressure leads to a lower freezing point. - Thus, this statement is **true**. ### Conclusion After analyzing all options: - **True Statements**: A, B, and D - **False Statement**: C ### Final Answer The true statements are **A, B, and D**. ---

To determine which of the given statements are true, let's analyze each option step by step. ### Step 1: Analyze Option A **Statement**: For the same solution, elevation in boiling point equals depression in freezing point. **Explanation**: - The elevation in boiling point (\( \Delta T_B \)) and depression in freezing point (\( \Delta T_F \)) can be expressed as: \[ ...
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CENGAGE CHEMISTRY ENGLISH-SOLUTIONS-Exercises (Multiple Correct)
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  2. Osmotic pressure of a solution is

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  4. Which of the following statements is/are correct?

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  5. For a non-volatile solute

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  6. To 10 mL of 1 M BaCl(2) solution 5mL of 0.5 M K(2)SO(4) is added. BaS...

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  10. Consider the two solutions: I: 0.5 M NaCl aqueous solution at 25^(@)...

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  11. Which pair(s) of liquids on mixing is/are expected to show no net volu...

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  12. The following is a graph plotted between the vapour pressure of two vo...

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  13. Consider the following solutions: I.1 M sucrose , II. 1 M KCl III...

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  14. The osmotic pressure of a solution depends on

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  15. 1.2575 g sample of [Cr(NH(3))(6)]SO(4)Cl(Mw=251.5) is dissolved to pre...

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  16. 2 L of 1 molal solution of a complex salt CrCl(3).6H(2)O (Mw=266.5) s...

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  18. Effect of adding a non-volatie solute to a solvent is"

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  19. Which of the following forms is an ideal solution?

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