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Assuming each salt to be 90% dissociated...

Assuming each salt to be `90%` dissociated which of the following will have the highest osmotic pressure?

A

Decinormal `Al_(2)(SO_(4))_(3)`

B

Decinormal `BaCl_(2)`

C

Decinormal `Na_(2)SO_(4)`

D

A solution obtained by mixing equal volumes of (b) and (c) and filtering

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To determine which salt will have the highest osmotic pressure when each salt is assumed to be 90% dissociated, we can follow these steps: ### Step 1: Understand the formula for osmotic pressure The osmotic pressure (\( \pi \)) of a solution can be calculated using the formula: \[ \pi = iCRT \] where: - \( i \) = van 't Hoff factor (number of particles the solute dissociates into) - \( C \) = molar concentration of the solution - \( R \) = universal gas constant - \( T \) = temperature in Kelvin ### Step 2: Identify the dissociation of each salt We need to determine the van 't Hoff factor (\( i \)) for each salt based on its dissociation in solution. The dissociation of the salts is as follows: 1. **NaCl** dissociates into 2 ions: \( Na^+ + Cl^- \) → \( i = 2 \) 2. **BaCl\(_2\)** dissociates into 3 ions: \( Ba^{2+} + 2Cl^- \) → \( i = 3 \) 3. **Na\(_2\)SO\(_4\)** dissociates into 3 ions: \( 2Na^+ + SO_4^{2-} \) → \( i = 3 \) 4. **MgSO\(_4\)** dissociates into 3 ions: \( Mg^{2+} + SO_4^{2-} \) → \( i = 3 \) 5. **Al\(_2\)(SO\(_4\))\(_3\)** dissociates into 5 ions: \( 2Al^{3+} + 3SO_4^{2-} \) → \( i = 5 \) ### Step 3: Calculate the effective van 't Hoff factor considering 90% dissociation Since each salt is 90% dissociated, we can calculate the effective \( i \) for each salt: - For **NaCl**: \( i = 2 \times 0.9 + 0.1 = 1.9 \) - For **BaCl\(_2\)**: \( i = 3 \times 0.9 + 0.1 = 2.7 \) - For **Na\(_2\)SO\(_4\)**: \( i = 3 \times 0.9 + 0.1 = 2.7 \) - For **MgSO\(_4\)**: \( i = 3 \times 0.9 + 0.1 = 2.7 \) - For **Al\(_2\)(SO\(_4\))\(_3\)**: \( i = 5 \times 0.9 + 0.1 = 4.6 \) ### Step 4: Compare the effective van 't Hoff factors Now we can compare the effective \( i \) values: - NaCl: \( i = 1.9 \) - BaCl\(_2\): \( i = 2.7 \) - Na\(_2\)SO\(_4\): \( i = 2.7 \) - MgSO\(_4\): \( i = 2.7 \) - Al\(_2\)(SO\(_4\))\(_3\): \( i = 4.6 \) ### Step 5: Determine the highest osmotic pressure Since osmotic pressure is directly proportional to the van 't Hoff factor (\( i \)), the salt with the highest \( i \) will have the highest osmotic pressure. From our calculations, **Al\(_2\)(SO\(_4\))\(_3\)** has the highest effective \( i \) of 4.6. ### Conclusion Thus, the salt that will have the highest osmotic pressure when each salt is assumed to be 90% dissociated is **Al\(_2\)(SO\(_4\))\(_3\)**. ---

To determine which salt will have the highest osmotic pressure when each salt is assumed to be 90% dissociated, we can follow these steps: ### Step 1: Understand the formula for osmotic pressure The osmotic pressure (\( \pi \)) of a solution can be calculated using the formula: \[ \pi = iCRT \] where: ...
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