On mixing `10 mL` of carbon tetrachloride with `10 mL` of benzene the total volume of the solution is:

Options

A. `gt20 mL`
B. `lt20 mL`
C. `=20 mL`
D. Cannot be predicted.

Explanation

To solve the problem of finding the total volume of a solution formed by mixing 10 mL of carbon tetrachloride (CCl4) with 10 mL of benzene (C6H6), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Components**:
- We have two liquids: carbon tetrachloride (CCl4) and benzene (C6H6).
- Each liquid has a volume of 10 mL.

2. **Ideal Solution Concept**:
- When two liquids form an ideal solution, the volume of the resulting solution is the sum of the volumes of the individual components.
- This is based on the assumption that there are no significant interactions between the molecules of the two liquids that would cause a change in volume upon mixing.

3. **Calculating the Total Volume**:
- Since both liquids are considered to form an ideal solution, we can simply add their volumes:
\[ \text{Total Volume} = \text{Volume of CCl4} + \text{Volume of C6H6} \]
- Substituting the values:
\[ \text{Total Volume} = 10 \, \text{mL} + 10 \, \text{mL} = 20 \, \text{mL} \]

4. **Conclusion**:
- Therefore, the total volume of the solution after mixing 10 mL of carbon tetrachloride with 10 mL of benzene is **20 mL**.

### Final Answer:
The total volume of the solution is **20 mL**.