The Van't Hoff factor of sulphur solution is …………..

Answer

To find the Van't Hoff factor (i) of a sulfur solution, we can follow these steps:

### Step 1: Understand the Van't Hoff Factor
The Van't Hoff factor (i) is defined as the ratio of the number of particles in solution after dissociation to the number of particles initially present before dissociation.

### Step 2: Analyze the Sulfur Solution
In the case of sulfur, we consider that sulfur exists as S8 molecules. When we dissolve sulfur in a solution, these S8 molecules do not dissociate into smaller particles but rather remain as whole molecules.

### Step 3: Initial and Equilibrium Moles
- **Initial Moles**: Let's assume we start with 1 mole of sulfur (S8).
- **Equilibrium Moles**: In solution, the S8 molecules remain intact, so at equilibrium, we still have 1 mole of S8.

### Step 4: Calculate the Van't Hoff Factor
Using the formula for the Van't Hoff factor:
\[ i = \frac{\text{Total moles at equilibrium}}{\text{Initial moles}} \]

Substituting the values:
- Total moles at equilibrium = 1 (since we have 1 mole of S8)
- Initial moles = 1

Thus,
\[ i = \frac{1}{1} = 1 \]

### Conclusion
The Van't Hoff factor (i) for the sulfur solution is **1**.

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