If excess of` Zn` is added to `1.0M` solution of `CuSO_(4)` , find the concentration of `Cu^(2+)` ions at equilibrium.
Given`:E^(c-)._((Zn^(2+)|Zn))=-0.76V`
`E^(c-)._(cell)=(E^(c-)._((Cu^(2+)|Cu))=0.34V`

Explanation

To solve the problem of finding the concentration of \( \text{Cu}^{2+} \) ions at equilibrium when excess zinc is added to a 1.0 M solution of \( \text{CuSO}_4 \), we can follow these steps:

### Step 1: Identify the half-reactions and their standard reduction potentials

The half-reactions involved are:
1. For zinc:
\[
\text{Zn}^{2+} + 2e^- \rightarrow \text{Zn} \quad (E^\circ = -0.76 \, \text{V})
...