Find the reduction potential of `AsO_(4)^(3-)|AsO_(2)^(c-)` in a solution when `18mL` of `0.1 N` solution of `NaI` is added to `20mL` of `0.1N Na_(3)AsO_(4)` solution at `pH=5.` The standard reduction potential of `AsO_(4)^(3-)|AsO_(2)^(c-)=-0.70V`.

Explanation

To find the reduction potential of the half-reaction \( \text{AsO}_4^{3-} | \text{AsO}_2^{-} \) when \( 18 \, \text{mL} \) of \( 0.1 \, N \) solution of \( \text{NaI} \) is added to \( 20 \, \text{mL} \) of \( 0.1 \, N \) solution of \( \text{Na}_3\text{AsO}_4 \) at \( pH = 5 \), we can follow these steps:

### Step 1: Calculate the number of milliequivalents of each reactant
1. **For \( \text{NaI} \)**:
\[ \text{Milliequivalents of NaI} = \text{Normality} \times \text{Volume} = 0.1 \, N \times 18 \, \text{mL} = 1.8 \, \text{mEq} \]

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