Calculate the `EMF` of the following concentration cells a `30^(@)C` and predict whether the cells are exergonic or endergonic. `[` Assume `Kw` does not chage at `30^(@)C]`
` Pt|H_(2)(g)(1 atm)|H^(o+)(10^(-6)M)||H^(o+)(10^(-4)M)|H_(2)(g)(1atm)|Pt`

Explanation

To calculate the EMF of the given concentration cell and determine whether the cell is exergonic or endergonic, we can follow these steps:

### Step 1: Identify the Cell Components
The cell is represented as:
\[ \text{Pt} | \text{H}_2(g)(1 \text{ atm}) | \text{H}^+(10^{-6} \text{ M}) || \text{H}^+(10^{-4} \text{ M}) | \text{H}_2(g)(1 \text{ atm}) | \text{Pt} \]

Here, the left side (anode) has a lower concentration of \( \text{H}^+ \) ions (10^-6 M) compared to the right side (cathode) which has a higher concentration (10^-4 M).

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