What is the volume of `O_(20` liberated at anode at `STP` in the electrolysis of `CdSO_(4)` solution when a current of `2 A` is passed for `8 m i n ?`

Explanation

To solve the problem of finding the volume of \( O_2 \) liberated at the anode during the electrolysis of \( CdSO_4 \) solution, we will follow these steps:

### Step 1: Calculate the total charge (Q) passed through the solution.
Given:
- Current (I) = 2 A
- Time (t) = 8 minutes = \( 8 \times 60 = 480 \) seconds

Using the formula:
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