`100mL `of `1M` solution of `CuBr_(2)` was electrolyzed with a current of `0.965` ampere hour. What is the normality of the remaining `CuBr_(2)` solution ?
`a. 1.64" "b.3.28" "c.0.82" "d.4.92`

Explanation

To solve the problem, we need to find the normality of the remaining CuBr₂ solution after electrolysis. Here’s a step-by-step breakdown of the solution:

### Step 1: Calculate the total charge passed during electrolysis
The charge (Q) can be calculated using the formula:
\[ Q = I \times t \]
where:
- \( I = 0.965 \, \text{A} \) (current)
- \( t = 3600 \, \text{s} \) (time in seconds)
...