A sodium salt of ternary acid of molybdenum `(` atomic mass `=96)` has the formula `Na_(2)MoO_(n)`. When an acidified solution of `Na_(2)MoO_(n)` is electrolyzed, `O_(2)` gas is liberated corresponding to a volume of `0.112L` at `STP` and `0.32g` of `Mo` is deposited. Find the formula of salt. .

Explanation

To find the formula of the sodium salt of the ternary acid of molybdenum, we need to analyze the information given in the question step by step.

### Step 1: Determine the moles of O2 gas liberated
We are given that 0.112 L of O2 gas is liberated at STP. At standard temperature and pressure (STP), 1 mole of gas occupies 22.4 L. Therefore, we can calculate the moles of O2:

\[ \text{Moles of } O_2 = \frac{\text{Volume of } O_2}{\text{Molar volume at STP}} = \frac{0.112 \, \text{L}}{22.4 \, \text{L/mol}} = 0.005 \, \text{mol} \]
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