`100mL CuSO_(4)(aq)` was electrolyzed using inert electrodes by passing `0.965A `till the `pH` of the resulting solution was 1. The solution after electrolysis was neutralized, treated with excess `KI` and titrated with `0.04M Na_(2)S_(2)O_(3)`. Volume of `Na_(2)S_(2)O_(3)` required was `35mL`. Assuming no volume change during electrolysis, calculate: duration of electrolysis if current efficiency is `80%`

Explanation

To solve the problem step by step, we will follow the given information and perform the necessary calculations.

### Step 1: Calculate the concentration of H⁺ ions
Given that the pH of the resulting solution after electrolysis is 1, we can find the concentration of H⁺ ions using the formula:
\[ \text{pH} = -\log[\text{H}^+] \]

From this, we can derive:
\[ [\text{H}^+] = 10^{-\text{pH}} = 10^{-1} \, \text{M} \]
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