`18.97 g` fused `SnCl_(2` was electrolyzed using inert electrodes. `1.187g Sn` was deposited at cathode. If nothing is obtained during electrolysis, calculate the ratio of weight of `SnCl_(2)` and `SnCl_(4)` in fused state after electrolysis.
Given`:`
Atomic weight of `Sn=118.7, Mw `of `SnCl_(2)=189.7, Mw` of `SnCl_(4)=260.7`

Explanation

To solve the problem step by step, we will follow the outlined process:

### Step 1: Understand the Electrolysis Reaction
The electrolysis of SnCl₂ leads to the formation of Sn and SnCl₄. The balanced reaction can be represented as:

\[ 2 \text{SnCl}_2 \rightarrow 2 \text{Sn} + \text{SnCl}_4 \]

### Step 2: Calculate Moles of Sn Deposited
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