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^^(m)^(0) for NaCl, HCl and NaAc are 126...

`^^_(m)^(0)` for NaCl, HCl and NaAc are 126.4, 425.9 and 91.0 S `cm^(2)" "mol^(-1)`
respectively. Calculate `(^^)^(0)` for `HAc`

Text Solution

Verified by Experts

`wedge_(m(HAc))^(@)=wedge_(m(HCl))^(@)wedge_(m(NaAc))^(@)+wedge_(m(NaCl))^(@)`
`=(425.9+91.0-126.4)S cm^(2)mol^(-1)`
`=390.5 S cm^(2) mol^(-1)`
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