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The equivalent conductance of Ba^(2+) an...

The equivalent conductance of `Ba^(2+)` and `Cl^(-)` are `76ohm^(-1) cm^(2) eq^(-1)` and `63.5 ohm^(-1) cm^(2)eq^(-1)`, respectively, at infinite dilution . The equivalent conductance `(` in `ohm^(-1) cm^(2)eq^(-1))` of `BaCl_(2)` at infinite dilution will be

A

`139.5`

B

`203.0`

C

`279.0`

D

`101.15`

Text Solution

Verified by Experts

The correct Answer is:
A
`wedge^(@)._(eq(BaCl_(2)))=lambda^(@)._(eq(Ba^(@+)))+lambda^(@)._(eq(Cl^(c-)))`
`=63.5+76=139.5 S cm^(2) eq^(-1)`
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