If `X` is the specific resistance of the solution and `N` is the normality of the solution, the equivalent conductivity of the solution is given by
(a)`(1000x)/(N)`
(b)`(1000)/(Nx)`
(c)`(1000N)/(x)`
(d)`(Nx)/(1000)`

Options

A. `(1000x)/(N)`
B. `(1000)/(Nx)`
C. `(1000N)/(x)`
D. `(Nx)/(1000)`

Explanation

To solve the problem regarding the equivalent conductivity of a solution given its specific resistance and normality, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Specific Resistance and Conductance**:
- The specific resistance of the solution is denoted as \( X \).
- The specific conductance (or conductivity) \( \kappa \) is the reciprocal of the specific resistance:
\[ \kappa = \frac{1}{X} \]

2. **Expression for Equivalent Conductivity**:
- The equivalent conductivity \( \Lambda \) of a solution can be expressed in terms of specific conductance and normality:
\[ \Lambda = \frac{\kappa \times 1000}{N} \]
where \( N \) is the normality of the solution.

3. **Substituting for Conductance**:
- Now, substituting the expression for \( \kappa \) into the equation for \( \Lambda \):
\[ \Lambda = \frac{\left(\frac{1}{X}\right) \times 1000}{N} \]

4. **Simplifying the Expression**:
- Simplifying the above expression gives:
\[ \Lambda = \frac{1000}{N \times X} \]

5. **Identifying the Correct Option**:
- The final expression for equivalent conductivity \( \Lambda \) is:
\[ \Lambda = \frac{1000}{N \times X} \]
- This matches with option (b):
\[ \text{(b) } \frac{1000}{N \times X} \]

### Conclusion:
The correct answer is option (b): \(\frac{1000}{N \times X}\).