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Given that I(2)+2e^(-) rarr 2I^(c-)," ...

Given that `I_(2)+2e^(-) rarr 2I^(c-)," "E^(c-)=0.54V`
`Br_(2)+2e^(-) rarr 2Br^(-)," "E^(c-)=1.69V`
Predict which of the following is true.

A

`I^(c-)` ions will be able to reduce bromine.

B

`Br^(c-)` ions will be able to reduce iodine.

C

Iodine will be able to reduce broming.

D

Bromine will be able to reduce iodide ions.

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The correct Answer is:
To solve the problem, we need to analyze the given half-reactions and their standard reduction potentials. The goal is to determine which species can reduce the other based on their reduction potentials. ### Step-by-Step Solution: 1. **Identify the Half-Reactions and Their Potentials:** - The first half-reaction is: \[ I_2 + 2e^- \rightarrow 2I^- \] with a standard reduction potential \( E^\circ = 0.54 \, V \). - The second half-reaction is: \[ Br_2 + 2e^- \rightarrow 2Br^- \] with a standard reduction potential \( E^\circ = 1.69 \, V \). 2. **Compare the Standard Reduction Potentials:** - The standard reduction potential for bromine (\( E^\circ = 1.69 \, V \)) is greater than that for iodine (\( E^\circ = 0.54 \, V \)). - This indicates that bromine is a stronger oxidizing agent than iodine. 3. **Determine Which Species Can Reduce the Other:** - A species with a higher reduction potential can reduce a species with a lower reduction potential. - Since \( Br_2 \) has a higher potential than \( I_2 \), it means \( Br_2 \) can reduce \( I^- \) to \( I_2 \). - Conversely, \( I^- \) cannot reduce \( Br_2 \) because it has a lower potential. 4. **Identify the Possible Statements:** - From the options given: - **(a)** \( I^- \) ions will be able to reduce bromine. - **(b)** \( Br^- \) ions will be able to reduce iodine. - **(c)** Iodine will be able to reduce bromine. - **(d)** Bromine will be able to reduce iodide ions. 5. **Evaluate the Statements:** - **(a)** False: \( I^- \) cannot reduce \( Br_2 \). - **(b)** False: \( Br^- \) cannot reduce \( I_2 \). - **(c)** False: Iodine cannot reduce bromine. - **(d)** True: Bromine can reduce iodide ions. 6. **Conclusion:** - The correct statement is that bromine will be able to reduce iodide ions. ### Final Answer: The correct statement is: **Bromine will be able to reduce iodide ions.**

To solve the problem, we need to analyze the given half-reactions and their standard reduction potentials. The goal is to determine which species can reduce the other based on their reduction potentials. ### Step-by-Step Solution: 1. **Identify the Half-Reactions and Their Potentials:** - The first half-reaction is: \[ I_2 + 2e^- \rightarrow 2I^- ...
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