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The reaction Cu^(2+)(aq)+2Cl^(-)(aq) rar...

The reaction `Cu^(2+)(aq)+2Cl^(-)(aq) rarr Cu(s)+Cl_(2)(g)` has `E^(c-)._(cell)=-1.03V`. This reaction

A

Can be made to produce electricity in voltaic cell

B

Can be made to occur in an electrolytic cell

C

Can occur in acidic medium only

D

Can occur in basic medium only.

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To analyze the given reaction and determine the conditions under which it can occur, we will follow these steps: ### Step 1: Identify the Reaction The reaction provided is: \[ \text{Cu}^{2+}(aq) + 2\text{Cl}^-(aq) \rightarrow \text{Cu}(s) + \text{Cl}_2(g) \] ### Step 2: Understand the Cell Potential The cell potential (\(E^{\circ}_{cell}\)) is given as -1.03 V. A negative cell potential indicates that the reaction is non-spontaneous under standard conditions. ### Step 3: Determine the Type of Cell Since the reaction is non-spontaneous (as indicated by the negative cell potential), it cannot occur spontaneously in a voltaic (galvanic) cell. Instead, it can be driven by an external source of energy, which is characteristic of an electrolytic cell. ### Step 4: Analyze the Medium The question also asks whether the reaction can occur in acidic or basic medium. The presence of \(Cu^{2+}\) and \(Cl^-\) ions does not specify a requirement for acidic or basic conditions for the reaction to proceed. Thus, it can occur in either medium, but the electrolytic cell setup will be required to drive the reaction. ### Conclusion 1. The reaction cannot produce electricity in a voltaic cell because it is non-spontaneous. 2. The reaction can occur in an electrolytic cell since it requires an external energy source. 3. The reaction can occur in both acidic and basic media. ### Final Answer The reaction can be made to occur in an electrolytic cell (Option B). ---

To analyze the given reaction and determine the conditions under which it can occur, we will follow these steps: ### Step 1: Identify the Reaction The reaction provided is: \[ \text{Cu}^{2+}(aq) + 2\text{Cl}^-(aq) \rightarrow \text{Cu}(s) + \text{Cl}_2(g) \] ### Step 2: Understand the Cell Potential The cell potential (\(E^{\circ}_{cell}\)) is given as -1.03 V. A negative cell potential indicates that the reaction is non-spontaneous under standard conditions. ...
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