The two `Pt` electrodes fitted in a conductance cell are `1.5 cm` apart while the cross`-` sectional area of each electrode is `0.75cm`. What is the cell constant?

Options

A. `1.125`
B. `0.5cm`
C. `2.0cm^(-1)`
D. `0.2cm^(-1)`

Explanation

To find the cell constant of the conductance cell, we can use the formula for the cell constant (G*), which is given by:

\[ G^* = \frac{L}{A} \]

where:
- \( L \) is the distance between the two electrodes (in cm),
- \( A \) is the cross-sectional area of the electrodes (in cm²).

### Step-by-Step Solution:

1. **Identify the values given in the problem:**
- Distance between the electrodes, \( L = 1.5 \, \text{cm} \)
- Cross-sectional area of each electrode, \( A = 0.75 \, \text{cm}^2 \)

2. **Substitute the values into the formula:**
\[ G^* = \frac{1.5 \, \text{cm}}{0.75 \, \text{cm}^2} \]

3. **Perform the division:**
\[ G^* = \frac{1.5}{0.75} = 2 \, \text{cm}^{-1} \]

4. **State the final result:**
The cell constant \( G^* \) is \( 2 \, \text{cm}^{-1} \).

### Final Answer:
The cell constant is \( 2 \, \text{cm}^{-1} \).

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