The products obtained at cathode and anode on electrolysis of aqueous sodium succinate are

Options

A. Anode `:` Ehene`+CO_(2)`, Cathode`:H_(2)`
B. Anode `:` Ethyne`+CO_(2)`,Cathode `:H_(2)`
C. Anode`:` Ethene`+H_(2)`, Cathode `:Na`
D. Anode`:` Ethyne `+H_(2)`, Cathode`:Na`

Explanation

To determine the products obtained at the cathode and anode during the electrolysis of aqueous sodium succinate (C4H6Na2O4), we can follow these steps:

### Step 1: Identify the Electrolysis Process
Electrolysis involves the decomposition of a compound in an aqueous solution using an electric current. In this case, we are dealing with sodium succinate.

### Step 2: Determine the Reactions at the Anode
At the anode, oxidation occurs. Sodium succinate can undergo oxidation, leading to the formation of ethene (C2H4) and carbon dioxide (CO2). The balanced reaction at the anode can be represented as:
\[ \text{C}_4\text{H}_6\text{Na}_2\text{O}_4 \rightarrow \text{C}_2\text{H}_4 + 2 \text{CO}_2 + 2 \text{Na}^+ + 2 e^- \]

### Step 3: Determine the Reactions at the Cathode
At the cathode, reduction occurs. In an aqueous solution, hydrogen ions (H+) are present, which will be reduced to form hydrogen gas (H2). The balanced reaction at the cathode is:
\[ 2 \text{H}^+ + 2 e^- \rightarrow \text{H}_2 \]

### Step 4: Summarize the Products
- **At the Anode**: The products are ethene (C2H4) and carbon dioxide (CO2).
- **At the Cathode**: The product is hydrogen gas (H2).

### Final Answer
- **Products at Anode**: Ethene (C2H4) and Carbon Dioxide (CO2)
- **Product at Cathode**: Hydrogen Gas (H2)

### Conclusion
The correct answer is:
- **Anode**: Ethene and Carbon Dioxide
- **Cathode**: Hydrogen Gas