A certain electrode has standard `(` reduction potential `)` of `0.384 V`. The potential when measured against a normal calomel electrode `(` with electrode potential`=0.28V)` is

Options

A. `0.104`
B. `0.664`
C. `0.3322`
D. `0.218`

Explanation

To solve the problem, we need to calculate the potential of a certain electrode when measured against a normal calomel electrode. Here are the steps to arrive at the solution:

### Step-by-step Solution:

1. **Identify the Given Values:**
- Standard reduction potential of the certain electrode (E₁) = 0.384 V
- Standard reduction potential of the normal calomel electrode (E₂) = 0.28 V

2. **Determine the Role of Each Electrode:**
- Since the standard reduction potential of the certain electrode (0.384 V) is higher than that of the calomel electrode (0.28 V), the certain electrode will act as the cathode, and the calomel electrode will act as the anode.

3. **Use the Formula for Cell Potential:**
- The cell potential (E_cell) can be calculated using the formula:
\[ E_{cell} = E_{cathode} - E_{anode} \]
- Here, E_cathode = E₁ = 0.384 V and E_anode = E₂ = 0.28 V.

4. **Substitute the Values into the Formula:**
\[ E_{cell} = 0.384 \, V - 0.28 \, V \]

5. **Calculate the Result:**
\[ E_{cell} = 0.104 \, V \]

6. **Conclusion:**
- The potential when measured against a normal calomel electrode is **0.104 V**.

### Final Answer:
The potential when measured against a normal calomel electrode is **0.104 V**.