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Given the ionic conductance of underset(...

Given the ionic conductance of `underset(underset(COO^(-))(|))(COO^(-)),K^(o+), ` and `Na^(o+)` are `74,50,` and `73cm^(2)ohm^(-1)eq^(-1)`, respectviley. The equivalent conductance at infinite dilution of the salt `underset(underset(COOK)(|))(COONa)` is

A

`197 cm^(2)ohm^(-1)eq^(-1)`

B

`172cm^(2)ohm^(-1)eq^(-1)`

C

`135.5cm^(2)ohm^(-1)eq^(-1)`

D

`160.5cm^(2)ohm^(-1)eq^(-1)`

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To find the equivalent conductance at infinite dilution of the salt \( \text{COOK} \) and \( \text{COONa} \), we will use the given ionic conductances of the ions involved. The ionic conductance values provided are: - \( \text{COO}^- \): \( 74 \, \text{cm}^2 \, \text{ohm}^{-1} \, \text{eq}^{-1} \) - \( \text{K}^+ \): \( 50 \, \text{cm}^2 \, \text{ohm}^{-1} \, \text{eq}^{-1} \) - \( \text{Na}^+ \): \( 73 \, \text{cm}^2 \, \text{ohm}^{-1} \, \text{eq}^{-1} \) ### Step 1: Determine the number of equivalents for each ion The equivalent of an ion is determined by the formula: \[ \text{Number of equivalents} = \frac{\text{Charge on ion}}{\text{Total charge}} \] 1. For \( \text{COO}^- \): - Charge on ion = 1 (since \( \text{COO}^- \) has a charge of -1) - Total charge = 1 (the total charge of the ion) - Number of equivalents = \( \frac{1}{1} = 1 \) 2. For \( \text{K}^+ \): - Charge on ion = 1 - Total charge = 1 - Number of equivalents = \( \frac{1}{1} = 1 \) 3. For \( \text{Na}^+ \): - Charge on ion = 1 - Total charge = 1 - Number of equivalents = \( \frac{1}{1} = 1 \) ### Step 2: Calculate the equivalent conductance at infinite dilution The formula for the equivalent conductance at infinite dilution \( \Lambda^0 \) of the salt \( \text{COOK} \) and \( \text{COONa} \) is given by: \[ \Lambda^0 = \frac{1}{2} \Lambda^0_{K^+} + \frac{1}{2} \Lambda^0_{Na^+} + \Lambda^0_{COO^-} \] Substituting the values: \[ \Lambda^0 = \frac{1}{2} \times 50 + \frac{1}{2} \times 73 + 74 \] ### Step 3: Perform the calculations 1. Calculate \( \frac{1}{2} \times 50 = 25 \) 2. Calculate \( \frac{1}{2} \times 73 = 36.5 \) 3. Now sum these values: \[ \Lambda^0 = 25 + 36.5 + 74 = 135.5 \, \text{cm}^2 \, \text{ohm}^{-1} \, \text{eq}^{-1} \] ### Final Answer The equivalent conductance at infinite dilution of the salt \( \text{COOK} \) and \( \text{COONa} \) is: \[ \Lambda^0 = 135.5 \, \text{cm}^2 \, \text{ohm}^{-1} \, \text{eq}^{-1} \]

To find the equivalent conductance at infinite dilution of the salt \( \text{COOK} \) and \( \text{COONa} \), we will use the given ionic conductances of the ions involved. The ionic conductance values provided are: - \( \text{COO}^- \): \( 74 \, \text{cm}^2 \, \text{ohm}^{-1} \, \text{eq}^{-1} \) - \( \text{K}^+ \): \( 50 \, \text{cm}^2 \, \text{ohm}^{-1} \, \text{eq}^{-1} \) - \( \text{Na}^+ \): \( 73 \, \text{cm}^2 \, \text{ohm}^{-1} \, \text{eq}^{-1} \) ### Step 1: Determine the number of equivalents for each ion The equivalent of an ion is determined by the formula: ...
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