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Given the standard potential of the foll...

Given the standard potential of the following at `25^(@)C`.
`MnO_(2) rarr Mn^(3+), " "E^(c-)=0.95V`
`Mn^(3+) rarr Mn^(2+)," "E^(c-)=1.51V`
The standard potential of `MnO_(2)rarr Mn^(2+)` is

A

`-0.56V`

B

`-2.46V`

C

`-1.23V`

D

`1.23V`

Text Solution

Verified by Experts

The correct Answer is:
d
`2e^(-) +MnO_(2) rarr Mn^(2+), E^(c-) =?`
`Delta G =-2FE^(c-)`
`i. e^(-)+MnO_(2) rarr Mn^(3+), DeltaG_(1)^(c-)=-Fe^(c-)=-0.95F`
`ii. e^(-) +Mn^(3+) rarr Mn^(3+), DeltaG_(2)^(c-)=-FE^(c-)=-1.51E^(c-)`
Equations `(i) +(ii)` give the desired equation.
`:. -2FE^(-) =(-0.95-1.51)F`
`E^(c-)1.23V`
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