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State True or false In highly alkaline ...

State True or false
In highly alkaline medium, the anodic process during the electrolytic process is
`4overset(c-)(O)H rarr O_(2)+2H_(2)O+4e^(-)`

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To determine whether the statement is true or false, we need to analyze the given anodic process in a highly alkaline medium. ### Step-by-Step Solution: 1. **Understanding the Anodic Process**: In an electrolytic cell, oxidation occurs at the anode. In a highly alkaline medium, hydroxyl ions (OH⁻) are present. 2. **Identifying the Reaction**: The given reaction is: \[ 4 \text{OH}^- \rightarrow \text{O}_2 + 2 \text{H}_2\text{O} + 4 e^- \] This indicates that four hydroxyl ions are being oxidized to produce one mole of oxygen gas, two moles of water, and four moles of electrons. 3. **Analyzing the Oxidation Process**: - Oxidation is defined as the loss of electrons. - In this reaction, the hydroxyl ions are losing electrons (4 electrons are produced), which confirms that oxidation is occurring. 4. **Conclusion**: Since the reaction correctly represents the oxidation of hydroxyl ions in a highly alkaline medium, the statement is true. ### Final Answer: The statement is **True**.

To determine whether the statement is true or false, we need to analyze the given anodic process in a highly alkaline medium. ### Step-by-Step Solution: 1. **Understanding the Anodic Process**: In an electrolytic cell, oxidation occurs at the anode. In a highly alkaline medium, hydroxyl ions (OH⁻) are present. 2. **Identifying the Reaction**: ...
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H_(2)O_(2) can be produced by the Ammonium hydrogen sulphate. Reactions occuring in electrolytic cell. NH_(4)HSO_(4) rarr NH_(4)^(+) +H^(+) +SO_(4)^(2-) 2SO_(4)^(2-) rarr S_(2)O_(8)^(2-) +2e^(-) (Anode) 2H^(+) +2e^(-) rarr H_(2) (cathode) (NH_(4))_(2)S_(2)O_(8) +2H_(2)O rarr 2NH_(4)HSO_(4) +H_(2)O_(2) Hydrolysis of Ammonium persulphate Assume 100% yield of hydrolysis reaction. What is the current efficiency when 100 Amp current is passed for 965 sec, in order to produce 17 gm of H_(2)O_(2) .

In a fuel cell, hydrogen and oxygen react to produce electricity. In process, hydrogen gas is oxidized at the anode and oxygen at the cathode. If 67.2L of H_(2) at STP reacts in 15mi n , what is the average current produced ? If the entire current is used for electro - deposition of copper from copper (II) solution, how many grams of copper will be deposited ? Anode reaction : H_(2)=2overset(c-)(O)Hrarr2H_(2)O+2e^(-) Cathode reaction :O_(2)+2H_(2)O+2e^(-) rarr 4overset(c-)(O)H

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H_(2)O_(2) can be produced by the ammonium hydrogen sulphate. Reactions occuring in electrolytic cell, NH_(4)HSO_(4)rarrNH_(4)^(-)+2e^(-) (Anode) 2SO_(4)^(2-)rarrS_(2)O_(8)^(2-)+2e^(-) 2H^(+)+2e^(-)rarrH_(2) (Cathode) Hydrolysis of ammonium persulphate: (NH_(4))_(2)S_(2)O_(8)+2H_(2)Orarr2NH_(4)HSO_(4)+H_(2)O_(2) Assume 100% yield of hydrolysis reaction. What volume of hydrogen gas at 1 atm and 273 K will be produced in cathode in previous question?

Hydrogen peroxide is a powerful oxidising agent, both in the acidic and alkaline medium. In acidic medium: H_(2)O_(2)+2H^(o+)+2e^(ɵ)to2H_(2)O In alkaline medium: H_(2)O_(2)+2e^(ɵ)to2overset(Theta)(O)H Hydrogen peroxide acts as a reducing agent towards powerful oxidising agents. In acidic medium: H_(2)O_(2)to2H^(o+)+O_(2)+2e^(ɵ) In alkaline medium, however, its reducing nature is more effective. H_(2)O_(2)to2H^(o+)+O_(2)+2e^(ɵ) In the reaction, H_2O_2 + O_3 to H_2O + 2O_2, H_2O_2 behaves as

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