State true or False
The cell potential becomes half if the cell reaction is divided by 2 througout.

Explanation

To determine whether the statement "The cell potential becomes half if the cell reaction is divided by 2 throughout" is true or false, we can analyze the properties of cell potential in electrochemistry.

### Step-by-Step Solution:

1. **Understanding Cell Potential**:
- Cell potential (E) is a measure of the driving force behind an electrochemical reaction. It is an intensive property, meaning it does not depend on the amount of substance present.

2. **Effect of Reaction Coefficients**:
- When we divide or multiply the coefficients of a balanced chemical equation by a constant, the overall reaction remains the same in terms of its thermodynamic properties. This includes the standard cell potential (E°).

3. **Example with Copper Reduction**:
- Consider the reduction of copper ions:
\[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu (s)} \quad (E° = 0.34 \, \text{V}) \]
- If we multiply the entire reaction by 2, we get:
\[ 2\text{Cu}^{2+} + 4e^- \rightarrow 2\text{Cu (s)} \]
- The standard cell potential (E°) remains the same at 0.34 V, even though the stoichiometry of the reaction has changed.

4. **Conclusion**:
- Since the cell potential does not change when the reaction is multiplied or divided by a constant, the statement that "the cell potential becomes half if the cell reaction is divided by 2 throughout" is **False**.

### Final Answer:
**False**