State True or false
The addition of `Br_(2)` to `NaI` turns the solution violet.

Explanation

To determine whether the statement "The addition of Br₂ to NaI turns the solution violet" is true or false, we can analyze the chemical reaction that occurs when bromine is added to sodium iodide (NaI).

### Step-by-Step Solution:

1. **Understanding the Reactants**:
- Sodium iodide (NaI) dissociates in solution to give sodium ions (Na⁺) and iodide ions (I⁻).
- Bromine (Br₂) is a diatomic molecule that can act as an oxidizing agent.

2. **Oxidation-Reduction Reaction**:
- Bromine (Br₂) has a higher reduction potential than iodide ions (I⁻). This means that Br₂ can oxidize I⁻ to iodine (I₂).
- The reaction can be represented as:
\[ Br_2 + 2I^- \rightarrow 2Br^- + I_2 \]
- In this reaction, the iodide ions (I⁻) are oxidized to iodine (I₂), while bromine (Br₂) is reduced to bromide ions (Br⁻).

3. **Color Change**:
- Iodine (I₂) in solution has a characteristic violet color. Therefore, when Br₂ reacts with NaI, the formation of I₂ will impart a violet color to the solution.

4. **Conclusion**:
- Since the addition of Br₂ to NaI results in the formation of iodine (I₂), which is violet in color, we conclude that the statement is true.

### Final Answer:
The statement is **True**.

---