The gas`X` at `1 atm` is bubbled through a solution containing a mixture of `1M Y^(-)` and `1M Z^(-)` at `25^(@)C` . If the order of reduction potential is `ZgtYgtX`, then

Options

A. `Y` will oxidize `X` and not `Z`
B. `Y` will oxidize `Z` and not `X`.
C. `Y` will oxidize both `X` and `Z`.
D. `Y` will reduct both `X` and `Z`.

Explanation

To solve the problem, we need to analyze the reduction potentials of the species involved and their ability to oxidize one another based on those potentials. Here’s a step-by-step breakdown:

### Step 1: Understand the Given Information
We have a gas `X` at `1 atm` that is bubbled through a solution containing a mixture of `1M Y^(-)` and `1M Z^(-)` at `25°C`. The order of reduction potentials is given as:
\[ Z > Y > X \]

### Step 2: Interpret Reduction Potentials
The reduction potential indicates the tendency of a species to gain electrons (be reduced). A higher reduction potential means a greater ability to be reduced. Conversely, a species with a lower reduction potential can be oxidized by a species with a higher reduction potential.

### Step 3: Analyze the Oxidizing Ability
From the order of reduction potentials:
- `Z` has the highest reduction potential, meaning it cannot be oxidized by either `Y` or `X`.
- `Y` has a higher reduction potential than `X`, which means `Y` can oxidize `X`.
- Since `Z` cannot be oxidized by `Y` or `X`, it remains unaffected.

### Step 4: Conclusion
Based on the analysis:
- `Y` can oxidize `X` because `Y` has a higher reduction potential than `X`.
- `Z` cannot be oxidized by either `Y` or `X` because it has the highest reduction potential.

Thus, the correct answer is that `Y` will oxidize `X` but not `Z`.

### Final Answer
**Y will oxidize X but not Z.**

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