In a catalyst experiment involving the Haber process `N_(2) + 3H_(2) rarr 2NH_(3)`, the rate of reaction was measured as
Rate `= (Delta[NH_(3)])/(Delta t) = 2.0 xx 10^(-4) mol L^(-1) s^(-1)`
What is the rate of reaction expressed in terms of (a) `N_(2)` (b) `H_(2)` ?

Explanation

To solve the problem, we need to express the rate of reaction in terms of the reactants \( N_2 \) and \( H_2 \) based on the given rate of formation of \( NH_3 \).

### Step-by-Step Solution:

1. **Write the balanced chemical equation:**
\[ N_2 + 3H_2 \rightarrow 2NH_3 \]
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