The rate of a reaction starting with initial concentration of `2 xx 10^(-3)` and `1 xx 10^(-3) M` are equal to `2.40 xx 10^(-4)` and `0.60 xx 10^(-4) M s^(-1)`, respectively. Calculate the order or reaction w.r.t. reactant and also the rate constant.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Write the rate equations for both reactions.
The rate of a reaction can be expressed as:
\[ r_1 = k [A]^a \]
\[ r_2 = k [B]^a \]
where:
- \( r_1 \) and \( r_2 \) are the rates of the reactions,
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