The rate of reaction: `2NO(g) + Cl_(2) (g) rarr 2NOCl (g)`, becomes doubled when the concentration of `Cl_(2)` is doubled. However, when the concentration of both the reactants are doubled, the rate becomes eight times. What is the order w.r.t. `NO` and w.r.t. chlorine ? What is the total order?

Explanation

To solve the problem, we need to determine the order of the reaction with respect to each reactant and the total order of the reaction. The reaction given is:

\[ 2NO(g) + Cl_2(g) \rightarrow 2NOCl(g) \]

### Step 1: Write the Rate Law Expression
The rate law expression for the reaction can be written as:

\[ \text{Rate} = k [NO]^a [Cl_2]^b \]
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