The `E_("cell")` of the reaction
`MnO_(4)^(-)+Fe^(+2)+H^(+)rarrMn^(2+)+H_(2)O` is 0.59 V at `25^(@)C` The equilibrium constant for the reaction is

Explanation

The reaction is :
`2Fe^(2+) + H_(2)O_(2) rarr 2Fe^(3) + 2overset(ɵ)(OH)`
Rate `= k[Fe^(2+)][H_(2)O_(2)]`
The machenism is :
`{:(Fe^(2+)H_(2)O_(2)overset(Slow)(rarr)Fe^(3+)+overset(o+)(O)H+OH),(Fe^(2+)+OHoverset("Fast")(rarr)Fe^(3+)+overset(o+)OH):}/{:(2Fe^(2+)+H_(2)O_(2)rarr2Fe^(3+)+overset(o+)2OH)/`