For the reaction of I, II and III orders, `k_(1) = k_(2) = k_(3)` when concentrations are expressed in mole `L^(-1)`. What will be the relation in `k_(1), k_(2), k_(3)`, if the concentration are expressed in `mol mL^(-1)`?

Explanation

To solve the problem, we need to determine the relationship between the rate constants \( k_1, k_2, \) and \( k_3 \) when the concentrations are expressed in \( \text{mol mL}^{-1} \) instead of \( \text{mol L}^{-1} \).

### Step-by-Step Solution:

1. **Understanding the Units**:
- The original rate constants \( k_1, k_2, k_3 \) are given when concentrations are in \( \text{mol L}^{-1} \).
- We need to convert these concentrations to \( \text{mol mL}^{-1} \).

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