`2A + 3B rarr `Product
a. What is the molecularity of the reaction?
b. What is order w.r.t. `A` and `B` in the following cases:
When `((dx)/(dt)) = k[A]` and `B` is in excess.

Explanation

a. In reaction `2A + 3B rarr` Product
Molecularity `= 5` (`5` molecules are colliding `2A` and `3B`)
b. i. When `(dx)/(dt) = k[A]`, order w.r.t. `A = 1` and order w.r.t. `B = 0`
ii. When `((dx)/(dt)) = k[B]^(2)`
Order w.r.t. `A = 0`,w.r.t. `b = 2`
iii. Rate `(r_(1)) = k[A]^(alpha)[B]^(beta)`
Case (i) `2r_(1) = k[2A]^(alpha)[B]^(beta)` ...(i)
Case (ii) `8r_(1) = k[2A]^(alpha)[2B]^(beta)` ...(ii)
form Eqs. (i) and (ii), we get
`alpha = 1, beta = 2`
`:.` Order w.r.t. `A = 1`
Order w.r.t. `B = 2`