The chemical reaction between mercuric chloride and potasisum oxalate proceeds as under:
`2HgCl_(2) + K_(2)C_(2)O_(4) rarr KCl + 2CO_(2) + Hg_(2)Cl_(2)`
The mass of `Hg_(2)Cl_(2)` precipitated form different solutions in a given time at `100^(@)C` was as follows:
`|{:("Experiment number",HgCl_(2) (mol L^(-1)),K_(2)C_(2)O_(4) (mol L^(-1)),"Time (min)",Hg_(2)Cl_(2) "precipitated (mole)"),(1,0.0836,0.404,65,0.0068),(2,0.0836,0.202,120,0.0031),(3,0.0418,0.404,60,0.0032):}|`
form the data calculate order of the reaction.

Explanation

To determine the order of the reaction between mercuric chloride (HgCl₂) and potassium oxalate (K₂C₂O₄), we will analyze the data provided from three experiments. We will calculate the rate of reaction for each experiment and then use these rates to find the order of the reaction with respect to each reactant.

### Step-by-Step Solution:

1. **Write the Rate Law Expression:**
The rate law for the reaction can be expressed as:
\[
\text{Rate} = k [\text{HgCl}_2]^x [\text{K}_2\text{C}_2\text{O}_4]^y
...