For a chemical reaction `A rarr` Products, the rate of reaction doubles when the concentration of `A` is increased by `4` times. The order of reaction is

Explanation

`r_(1) = k[A]^(n)` …(i)
`r_(2) =2r_(1) = k[4A]^(n)` …(ii)
Divide Eq. (ii) by Eq. (i)
`(2r_(1))/(r_(1)) = (k[4A]^(n))/(k[A]^(n))`
`2 = (4)^(n) rArr (2)^(1) = (2)^(2n) rArr 2n = 1 rArr n = (1)/(2)`
Order of reaction `= (1)/(2) Rate = k[A]^(1)/(2)`