For the reaction:
`2NOCl(g) rarr 2NO(g) + Cl_(2) (g)`, the mixture containing equilmolar mixture of `NO` and `Cl_(2)` gases at `0.15 atm` was half changed in `175 s`. In an another experiment, with an initial at `0.35 atm`, the mixture was half changed in `75 s`. Find the order of reaction.

Explanation

To solve the problem, we need to determine the order of the reaction based on the given data about the half-life of the reaction at different pressures.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
The reaction is given as:
\[
2NOCl(g) \rightarrow 2NO(g) + Cl_2(g)
...